All 45 questions, with what each one tests. Try any of them free in Gedara Sir to check your answer, with step-by-step working.
Total man-days from work done for part of a task
60 man-days
💡 What it's asking: A 'man-day' is the work one person does in one day. Find the man-days in the part that was done, then scale up to the whole task.
- Work done so far: 4 men × 5 days = 20 man-days.
- That 20 man-days is only 1/3 of the whole task.
- The whole task is 3 times as much: 20 × 3 = 60 man-days.
✅ One third of 60 is 20, which matches the work the 4 men did in 5 days.
සිංහලෙන් විසඳුම
'මිනිස් දිනය' යනු එක් අයෙකු දිනකදී කරන වැඩ ප්‍රමාණයයි. කළ කොටසේ මිනිස් දින සොයා, මුළු කාර්යයට වැඩි කරන්න.
- මෙතෙක් කළ වැඩ: මිනිසුන් 4 × දින 5 = මිනිස් දින 20.
- එම මිනිස් දින 20 මුළු කාර්යයෙන් 1/3 ක් පමණි.
- මුළු කාර්යය එමෙන් තුන් ගුණයකි: 20 × 3 = මිනිස් දින 60.
Unknown angle at intersecting perpendicular lines
x = 80°
💡 What it's asking: Perpendicular lines meet at a right angle (90°). The right angle here is split into two pieces, one of which is x.
- AB is perpendicular to CD, so the angle between OB and OD is 90°.
- That 90° is made of the 10° angle and x.
- So x = 90° − 10° = 80°.
✅ Add the pieces: 80° + 10° = 90°, a right angle.
සිංහලෙන් විසඳුම
ලම්බ රේඛා හමු වන්නේ සෘජු කෝණයකින් (90°). මෙහි සෘජු කෝණය කොටස් දෙකකට බෙදී ඇති අතර එකක් x වේ.
- AB රේඛාව CD ට ලම්බයි; එබැවින් OB හා OD අතර කෝණය 90° යි.
- එම 90° සෑදී ඇත්තේ 10° කෝණයෙන් සහ x ගෙනි.
- එබැවින් x = 90° − 10° = 80°.
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Cylinder water volume poured into a cuboid tank
Graphs · Algebraic InequalitiesGraph a line, read gradient and intercept, shade an inequality region
Grouped frequency table, modal class and mean
Algebraic Fractions · Least Common Multiple of Algebraic ExpressionsAdd and subtract algebraic fractions
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Extra time needed at a constant work rate
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Prove an angle relation in a quadrilateral with isosceles and equilateral parts
Construct a triangle and angle bisectors; verify by calculation
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Filling time of a tank at a given pump rate
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List sets, Venn diagram, unions, intersections and complements
