ප්රශ්න 31ම, එක් එක් ප්රශ්නය පරීක්ෂා කරන දේ සමඟ. ඕනෑම එකක් ගෙදර සර් තුළ නොමිලේ උත්සාහ කර ඔබේ පිළිතුර පරීක්ෂා කරන්න.
Choose the closest approximation of a square root

(ii) 3.2
💡 ප්රශ්නයේ අදහස: 10 කුමන වර්ග දෙක අතරදැයි සොයා, විකල්ප වර්ග කර 10 ට ළඟම එක තෝරන්න.
- 9 < 10 < 16 නිසා √10, 3 සහ 4 අතර, 3 ට ටිකක් වැඩියි.
- විකල්ප වර්ග කරන්න: 3.1² = 9.61, 3.2² = 10.24.
- 10.24, 10 සිට 0.24 දුරින්; 9.61, 0.39 දුරින්.
- 3.2 ළඟයි: (ii) 3.2 තෝරන්න.
✅ 3.2 × 3.2 = 10.24, 10 ට ටිකක් වැඩියි. ✓
Working in English
Find which squares 10 lies between, then square the choices to see which lands closest to 10.
- 9 < 10 < 16, so √10 is between 3 and 4, a little more than 3.
- Square the choices: 3.1² = 9.61 and 3.2² = 10.24.
- 10.24 is 0.24 away from 10; 9.61 is 0.39 away.
- 3.2 is closer: choose (ii) 3.2.
Radius of a sector from its arc length and perimeter

r = 7 cm
💡 ප්රශ්නයේ අදහස: කේන්ද්රික ඛණ්ඩයක පරිමිතිය = චාපය + අරය දෙක. චාපය අඩු කර ඉතිරිය අඩ කරන්න.
- පරිමිතිය = r + r + චාපය = 2r + 11.
- 11 අඩු කරන්න: 2r + 11 = 25; 2r = 14.
- ඒ නිසා r = 7 cm.
✅ පරිමිතිය පරීක්ෂා කරන්න: 7 + 7 + 11 = 25 cm. ✓
Working in English
A sector's perimeter is the arc plus two radii. Take away the arc and halve what's left.
- Perimeter = r + r + arc = 2r + 11.
- 2r + 11 = 25, so 2r = 14.
- r = 7 cm.
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